**Hitoshi Kitada** (*hitoshi@kitada.com*)

*Mon, 6 Sep 1999 11:00:00 +0900*

**Messages sorted by:**[ date ] [ thread ] [ subject ] [ author ]**Next message:**Stephen P. King: "[time 677] Re: [time 673]Stephen's duality theory, Plus Infinite Products = Infinite Worlds"**Previous message:**WDEshleman@aol.com: "[time 675] Infinite Objective Reality"**Next in thread:**Stephen P. King: "[time 678] Re: [time 676] Reply to NOW/PAST question"

Dear Bill,

I have a question.

Bill <WDEshleman@aol.com> wrote:

Subject: [time 674] Re: [time 664] Reply to NOW/PAST question

*> Matti,
*

*> Here is some fixing up.
*

*> Bill
*

*>
*

*> [MP]
*

*> a) I could not quite understand you NOW= PAST + x*PAST. If one starts
*

*> from Schrodinger equation one has -i dPsi/dt= HPsi.
*

*> Psi(t+deltat) = Psi(t) + i*HPsi(t)*Deltat = (1+ iH*delta t )*Psi(t)
*

*>
*

*> What troubles me is the identification of x. I would identify
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*> it as operator. My formula was also for infinitesimal time interval
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*> delta t. Perhaps we understand by z quite different things.
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*>
*

*> [WDE]
*

*> Yes, the name operator for v^2/c^2 is imprecise, it is a true factor,
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*> not the mathematical convenience, operator. Let me try to escape
*

*> this imprecision. First evaluate the operator and write it this way:
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*>
*

*> Psi(t+Deltat) = Psi(t) + [ i*HPsi(t) ] * Deltat
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*>
*

*> normalize,
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*>
*

*> Psi(t+Deltat) = Psi(t) + [ i*HPsi(t) / Psi(t) ] * Deltat * Psi(t)
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*>
*

*> then x = [ i*HPsi(t) / Psi(t) ] * Deltat
*

If you set like this, this x is equal to

x = - i Deltat H.

(You forgot minus sign in the above).

In this setting, we have an exact identity

Psi(t+Deltat) = exp(-i Deltat H) Psi(t) = exp (x) Psi(t)

according to the Schroedinger equation. This equals

Psi(t+Deltat) = (1+ x + x^2/2! + x^3/3! + x^4/4! + ...) Psi(t),

which seems different from your calculation:

*> Psi(t+Deltat)/Psi(t) = [ 1/(1 - x) ],
*

i.e.

Psi(t+Deltat)=(1+x+x^2+x^3+x^4+...)Psi(t)

Do you mean to imply what we actually observe is different from the exact

physical process to this amount? If so, then why/how?

*>
*

*> I cannot think of a name other than "operator", but Stephen
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*> might call it a "propagator". It is simply just a factor.
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*> And,
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*>
*

*> Psi(t+Deltat) = Psi(t) + x * Psi(t)
*

*>
*

*> But what I suggest is that we subjectively see,
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*>
*

*> Psi(t+Deltat) = Psi(t) + x * Psi(t+Deltat)
*

*> = Psi(t)
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*> + [ i*HPsi(t+Deltat) / Psi(t+Deltat) ] * Deltat * Psi(t+Deltat)
*

*>
*

*> or, Psi(t+Deltat)/Psi(t) = [ 1/(1 - x) ]
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*> = 1/ { 1 - [ i*HPsi(t+Deltat) ] * Deltat / Psi(t+Deltat) }
*

*>
*

*> or, Psi(t+Deltat)
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*> = Psi(t) / { 1 - [ i*HPsi(t+Deltat) ] * Deltat / Psi(t+Deltat) }
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*>
*

*> because of an objective multiplicity of other-worlds that
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*> trick observers into believing that the NOW is attracted
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*> to the FUTURE.
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*>
*

*> Matti,
*

*> If I made another error in the algebra, please don't give up.
*

*>
*

*> [MP]
*

*> Is your fomula really consistent with Schrodinger equation?
*

*>
*

*> [WDE]
*

*> I suspect not, but it might be, and I suggest that it should be.
*

*>
*

*> Sincerely,
*

*>
*

*> Bill
*

*>
*

*>
*

Best wishes,

Hitoshi

**Next message:**Stephen P. King: "[time 677] Re: [time 673]Stephen's duality theory, Plus Infinite Products = Infinite Worlds"**Previous message:**WDEshleman@aol.com: "[time 675] Infinite Objective Reality"**Next in thread:**Stephen P. King: "[time 678] Re: [time 676] Reply to NOW/PAST question"

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