# [time 678] Re: [time 676] Reply to NOW/PAST question

Stephen P. King (stephenk1@home.com)
Mon, 06 Sep 1999 02:26:43 -0400

Hi All,

> If you set like this, this x is equal to
>
> x = - i Deltat H.
>
> (You forgot minus sign in the above).
>
> In this setting, we have an exact identity
>
> Psi(t+Deltat) = exp(-i Deltat H) Psi(t) = exp (x) Psi(t)
>
> according to the Schroedinger equation. This equals
>
> Psi(t+Deltat) = (1+ x + x^2/2! + x^3/3! + x^4/4! + ...) Psi(t),
>
> which seems different from your calculation:
>
> > Psi(t+Deltat)/Psi(t) = [ 1/(1 - x) ],
>
> i.e.
>
> Psi(t+Deltat)=(1+x+x^2+x^3+x^4+...)Psi(t)
>
> Do you mean to imply what we actually observe is different from the exact
> physical process to this amount? If so, then why/how?

What is the difference? Does it diverge or converge or neither as x ->
\infinity?

Bill, what if every observer related to the values v and c in (v^2/c^2)
could only interfere with a finite number of other observers, but there
exist at least an infinity of them?

Puzzled!

Stephen

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